A joker’s cap is in the form of right circular cone whose base radius is 7 cm and height is 24 cm. Find the area of the sheet required to make 10 such caps.

Given that, the radius of cone(r) is 7 cm and height(h) is
24 cm.
And, Surface area of cone is - πrl
Also, slant height(l) = √ r2 + h2
⇒ l = √ 72 + 242
⇒ l = √ 49 + 576
⇒ l = √ 625
⇒ l = 25
⇒ Surface area of joker’s cap![]()
= 550cm2
⇒ ∴ the area of the sheet required to make 10 such caps
= 550 × 10 cm2
= 5500 cm2
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