The shape of solid iron rod is a cylindrical. Its height is 11 cm. and base diameter is 7 cm. Then find the total volume of 50 such rods?

Given that, height(h) of cylinder is 11 cm and diameter(d) is 7 cm.
⇒ radius(r) of cylinder![]()
And, the volume of cylinder = πr2h
⇒ volume of one rod![]()
⇒ volume of one rod![]()
= 423.5
⇒ the total volume of 50 such rods = 423.5 × 50
= 21,175cm3
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