A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1.2.3.4.5.6.7.8 (Sec figure), and these are equally likely outcomes. What is the probability that it will point at

an odd number?
Total numbers = 8
⇒ Total odd numbers = (1,3,5,7)
⇒ Number of favourable cases = 4
⇒ P( an odd number) = ![]()
⇒ P( an odd number) = ![]()
⇒ P( an odd number) = ![]()
∴ Probability arrow will point an odd number will be ![]()
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