12 defective pens are accidentally mixed with 132 good ones. It is not possible to just look at a pen and tell whether or not is defective. One pen is taken out at random from this lot. Determine the probability that the pen taken out is a good one.
Given,
⇒ Total defective pens = 12
⇒ Total good pens = 132
∴ number of favourable cases = 132
⇒ Total number of pens = 12 + 132
⇒ Total number of pens = 144
⇒ Number of total outcomes will 144.
⇒ Probability that the pen taken out is a good one = ![]()
⇒ P(pen taken out is good one) = ![]()
⇒ P(pen taken out is good one) = ![]()
∴ Probability of pen taken out is good one is ![]()
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