A die is thrown twice. What is the probability that
5 will not come up either time?
[Hint : Throwing a die twice and throwing two dice simultaneously are treated as the same experiment ].
If a dice thrown ‘n’ times then total number of outcome = 6n
⇒ Dice is thrown 2 times then total outcomes = 62
⇒ Dice is thrown 2 times then total outcomes = 36
⇒ Favourable outcomes where 5 will not come up either time = (1,1)(1,2)(1,3)(1,4)(1,6)(2,1)(2,2)(2,3)(2,4)(2,6)(3,1)(3,2)(3,3)(3,4)(3,6)(4,1)(4,2)(4,3)(4,4)(4,6)(6,1)(6,2)(6,3)(6,4)(6,6).
⇒ Number of favourable events = 25
⇒ Probability 5 will not come up either time –
⇒ P(5 will not come up either time)=![]()
⇒ P(5 will not come up either time)=![]()
∴ Probability 5 will not come up either time is
.
Couldn't generate an explanation.
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