A box contains 90 discs which are numbered from 1 to 90. If one disc is selected at random from the box, find the probability that it bears.
a perfect square number
There are 90 discs in a box.
⇒ Number of outcomes in which discs is selected = 90.
⇒ Total perfect square in the box –
⇒ 12 = 1
⇒ 22 = 4
⇒ 32 = 9
⇒ 42 = 16
⇒ 52 = 25
⇒ 62 = 36
⇒ 72 = 49
⇒ 82 = 64
⇒ 92 = 81
⇒ Number of favourable cases = 9
⇒ Probability that discs bears a perfect square number –
⇒ P(Perfect square numbers) = ![]()
⇒ P(Perfect square numbers) = ![]()
⇒ P(Perfect square numbers) = ![]()
∴ Probability that discs bears a perfect square number is ![]()
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.
