If 345 A 7 is divisible by 3, supply the missing digit in place of ‘A’.

Given, a number 345A7 divisible by 3

Need to find out A

⇒ Sum of the digits of 345A7 must be divisible by 3

3 + 4 + 5 + A + 7 = 19 + A must be divided by 3

Substitute A value from 0 to 9 by trial error method, we get

A might be 2 or 5 or 8

If A = 2 then 19 + 2 = 21 is divisible by 3.

If A = 5 then 19 + 5 = 24 is divisible by 3.

If A = 8 then 19 + 8 = 27 is divisible by 3.

Hence, A might be 2 or 5 or 8