27Q leaves remainder 3 when divided by 5 and leaves remainder 1 when divided by 2, what is the remainder when it is divided by 3 ?

Given, 27Q leaves a remainder 3 when divided by 5 and leaves remainder 1 when divided by 2

Need to find out the remainder when divided by3

Substitute Q value from trial error method from 0 to 9

⇒ Q = 3 when substituted in the given number

⇒ 27Q = 273 is divided by 5 and get the remainder as 3

⇒ 273 is divided by 2 and get the remainder as 1

Satisfies the above equation.

⇒ 273 is divided by 3 and we get the remainder as 0.

Hence, when 27Q = 273 is divided by 3 we get 0 as the remainder.