Check whether 1435 is divisible by 5 and 7? Verify if 1435 is divisible by the product of 5 and 7?
Given, “1435” a number.
Need to find out it is divisible by 5 and 7 and also by product 5 × 7
⇒ 1435 is divisible by 5. Since, units digit of the number is 5.
⇒ Now, we know (6a + 2b + 3c + d) by divisibility rule
⇒ 6(1) + 2(4) + 3(3) + 5 = 6 + 8 + 9 + 5
= 28 is divisible by 7
∴ 1435 is divisible by 7
The product of 5,7 is 35
∴ 1435 is divisible by 35 because it is divisible by 5 and divisible by 7.
Hence, 1435 is divisible by 5 and 7 and divisible by the product of 5 and 7.
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