If ABB × 999 = ABC123 (where A, B, C are digits) find the values of A, B, C.

Given, product of ABB and 999 = ABC123

Need to find out the values of A, B, C

We know that 7 × 9 = 63

So, ABB must be a number ending with 7

⇒ A77 × 999 = ABC123

Let us consider it A77 be 877 by trial and error method

∴ 877 × 999 = 876123

⇒ ABC123 = 876123

∴ A = 8, B = 7 and C = 6