i. If A = Φ, find n[P(A)]
ii. If n(A) = 3, find n[P(A)]
iii. If n[P(A)] = 512 find n(A)
iv. If n[P(A)] = 1024 find n(A)
As we have seen in the previous problems, the number of elements in the power set are 2n elements, while there are n elements in the current set. Similarly, if there are n elements in the power set, then there will be Log2(n) elements in the current set.
i. 20 =1
ii. 23 =8
iii. Log2(512)=9
iv. Log2(1024)=10
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