A and B are two sets such that n(A – B) = 32 + x, n (B – A) = 5x and n(A B) = x Illustrate the information by means of a Venn diagram. Given that n(A) = n(B). Calculate (i) the value of x (ii) n(A B).
Given that
n(A–B) = 32 + x
n(B–A) = 5x
n(A∩B) = x
and n(A) = n(B)
using these results
n(A) = n(A–B) + n(A∩B)
n(B) = n(B–A) + n(A∩B)
n(A∪B) = n(A–B) + n(A∩B) + n(B–A)
But given that n(A) = n(B)
So, n(A–B) + n(A∩B) = n(B–A) + n(A∩B)
n(A–B) = n(B–A)
32 + x = 5x
5x–x = 32
4x = 32
(i) x = 32/4 = 8
(ii) n(A∪B) = n(A–B) + n(A∩B) + n(B–A)
= 32 + x + x + 5x
= 32 + 7x
= 32 + 7(8)
= 88
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