In the figure, ABC is a triangle in which AB = AC. Find x° and y°.

Theorem 2:
If a side of a triangle is produced, the exterior angle so formed, is equal to the sum of the two interior angle.
∠ ACE + ∠ ACB = 180°
⇒ x + 48° + x° = 180°
⇒ 2x + 48° = 180°
⇒ 2x = 180° - 48°
⇒ 2x = 132°
⇒ ![]()
⇒ x = 66°
Ext. ∠ A = ∠ B + ∠ C
⇒ y° = x° + x°
⇒ y° = 2x°
⇒ y° = 2 × 66°
⇒ y° = 132°
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