Find x°, y°, z° from the figure, where AB = BD, BC = DC and ∠DAC 30o.

Theorem 1: Sum of all the angles in the triangle is 180°.
In Δ ABD,
We know that, AB = BD
∴ ∠ A = ∠ D
⇒ 30° = x°
Hence, ∠ A + ∠ B + ∠ C = 180°
⇒ 30° + ∠ B + 30° = 180°
⇒ ∠ B + 60° = 180°
⇒ ∠ B = 180° - 60°
⇒ ∠ B = 120°
∠ DBA + ∠ DBC = 180° (Sum of adjacent angles is 180°)
⇒ 120° + y° = 180°
⇒ y° = 180° - 120°
⇒ y° = 60°
In Δ DBC
We know that, BC = DC
∴ ∠ B = ∠ D
⇒ y° = z°
⇒ 60° = z°
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