For each pair of polynomials below, find the quotient and remainder on dividing the first by the second.
x3 – 1, x + 1
Given, x3 – 1, x – 1 as pair of polynomials
Need to find the quotient and remainder
⇒ To find the quotient and remainder the given equation can be written as p(x) = (x – a)q(x) + b
⇒ Since, the polynomial is of third degree we can write the q(x) as x2 + ax + b
∴ p(x) = (x – a)( x2 + ax + b) + c
⇒ x3 – 1 = (x + 1)( x2 + ax + b) + c
⇒ x3 – 1 = (x3 + x2 + ax2 + ax + bx + b) + c
⇒ x3 – 1 = x3 + (a + 1)x2 + (a + b)x + (c + b)
∴ a + 1 = 0, a + b = 0, c + b = – 1
⇒ a = – 1
⇒ a + b = 0
⇒ – 1 + b = 0
⇒ b = 1
⇒ c + b = – 1
⇒ c + 1 = – 1
⇒ c = – 2
Quotient = x2 + ax + b = x2 – x + 1
Remainder = – 2
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