Q4 of 31 Page 245

In each pair of polynomials below find what kind of natural number n must be, so that the first is a factor of the second.

x – 1, xn + 1

Given, x – 1, xn + 1 pair of polynomials


Need to find out n such as first polynomial is factor of second


⇒ To check x – 1 is factor of xn + 1 we must get xn + 1 = 0 when substituted x with 1 from the first polynomial


⇒ Consider n as 1 then the polynomial equation wiil be x + 1 which is not equal to zero and x – 1 will not be the factor.


⇒ For any n value x – 1 cannot be a factor


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