For each pair of polynomials below, find the quotient and remainder on dividing the first by the second.
x3 + 1, x – 1
Given, x3 – 1, x – 1 as pair of polynomials
Need to find the quotient and remainder
⇒ To find the quotient and remainder the given equation can be written as p(x) = (x – a)q(x) + b
⇒ Since, the polynomial is of third degree we can write the q(x) as x2 + ax + b
∴ p(x) = (x – a)( x2 + ax + b) + c
⇒ x3 + 1 = (x – 1)(x2 + ax + b) + c
⇒ x3 + 1 = (x3 –x2 + ax2 – ax + bx – b) + c
⇒ x3 + 1 = x3 + (a–1)x2 + (b – a)x + (c – b)
∴ a – 1 = 0, b – a = 0, c – b = 1
⇒ a = 1, b = 1
⇒ c – b = 1
⇒ c = 2
Quotient = x2 + ax + b = x2 + x + 1
Remainder = 2
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