By adding a number to p(x) = x3 + x2 + x, a new polynomial q(x) is to be formed.
What number should be added, so that x – 1 is a factor of q(x)?
Given p(x) = x3 + x2 + x
Let the number to be added be “k”.
Then, the new polynomial q(x) = x3 + x2 + x + k
Now, (x – 1) is a factor of x3 + x2 + x + k.
i.e. x = 1 is the root of the polynomial.
Then, put the polynomial to zero we get,
x3 + x2 + x + k = 0
⇒ (1)3 + (1)2 + 1 + k = 0
⇒ 1 + 1+1 + k = 0
⇒ k = – 3
Hence, “ – 3” should be added to the polynomial such that (x – 1) is a factor of q(x).
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