A mathematician travelled three hundred kilometres to attend a conference. During his take he said: “Had my average speed been increased by 10 kilometres per hour, I could have reached here one hour earlier.” What was the average speed?
Given.
Distance = 100km
If average speed been increased by 10 kilometres per hour, I could have reached here one hour earlier
Formula used.
Average speed = 
Let the sum of time taken be x
Average speed = 
New average speed = average speed + 10
+ 10
10x = (x–1)(10 + x)
10x = 10x + x2–10–x
x2–x–10 = 10x–10x = 0
x2–x–10 = 0
As comparing eq to ax2 + bx + c = 0
x = 
x = 
= = 
As √41 is greater than 1
∴ time cannot get negative
Hence; time is 
hours
Average speed = 
Couldn't generate an explanation.
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