Can the sum of a number and its reciprocal be
? Why?
Let the number be x
Then reciprocal of number is ![]()
If reciprocal number, added to the number itself
Then;
(x +
) =
= 1![]()
∴ comparing both
![]()
⇒ 2x2 + 2 = 3x
2x2–3x + 2 = 0
As comparing eq to ax2 + bx + c = 0
x = ![]()
x = ![]()
⇒ Both values of x comes with non-real number
Their can’t be negative sign in square root
∴ this number cannot be possible
Conclusion/Result. This type of number cannot be possible
Couldn't generate an explanation.
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