The reciprocal of a positive number, subtracted from the number itself gives
. What is the number?
Let the number be x
Then reciprocal of number is ![]()
If reciprocal number, subtracted from the number itself is 1![]()
Then;
(x–
) =
= 1![]()
∴ comparing both
![]()
x = 2
x2–1 = 3
x2 = 4
x = √4 = 2
∴ the number is 2
Conclusion/Result. Number comes out to be 2
Couldn't generate an explanation.
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