Q5 of 27 Page 97

In writing the equation to construct a rectangle of specified perimeter and area, the perimeter was wrongly written as 24 instead of 42. The length of a side was then computed as 10 metres. What is the area in the problem? What are the lengths of the rectangle in the correct problem?

Given.


Perimeter was wrongly written as 24 instead of 42.


The length of a side was then computed as 10 metres


Formula used/Theory


Perimeter of rectangle = 2(L + B)


Area of rectangle = (L×B)


If Perimeter of rectangle is taken as 24 m


And the length computed was 10 m


2(L + B) = 24m


(L + B) = = 12m


(10 + B) = 12m


B = 12m–10m = 2m


Then Area computed in problem was = (L×B)


= 10m×2m


= 20m2


Corrected perimeter = 42m


2(L + B) = 42m


(L + B) = = 21m


If area computed is 20m2 and sum of length and breadth is 21m


Then;


The sides comes out to be 20m and 1m


Conclusion/Result. The sides comes out to be 20m and 1m


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