Draw a square of area square centimetres.

Given area of the square = 4. cm²

We know that area of the square = × d²

d is the diagonal of the square

× d² = 4.

d² = 9

d = 3 cm

diagonal of the square = 3 cm

step – 1:

Draw the a horizonal line with the starting point as A and draw 45^o ray from point A.

(It is a square so, the angle between side and diagonal will be 90^o)

Step – 2:

We know the length of diagonal, so cut the ray with 3 cm arc

Step – 3:

Connect the intersecting point with horizontal line and name the intersection point as O

The above fig. forms a right-angle triangle

Sin 45^o =

BO =

In square all sides are equal we can draw rest of the fig. with the same measurement.

Thus, a square can be drawn when its area is given.