A 68-centimeter-long rope is used to make a rhombus on the ground. The distance between a pair of opposite corners is 16 meters.
i) What is the distance between the other two corners?
ii) What is the area of the ground bounded by the rope?
68-centimeter-long rope is used to make a rhombus
The above statement states that perimeter of the rhombus is 68 cm.
And they have given that diagonal (d1) is 16 cm
(In question they have given that as meter that should be a meter)
Perimeter = 4 × a
Where,
a = side of the rhombus.
68 = 4a
a = 17 cm

From the triangle AOD
AD2 = AO2 + OD2
172 = 82 + X2
X = √(289-64)
= 15
(i) The distance between the other two corners (d2) = 2X
= 2 × 15
= 30 cm
(ii)The area of the rhombus =
×
× ![]()
=
×
× ![]()
= 60 cm2
Couldn't generate an explanation.
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