The area of a rhombus is 216 square centimetres and the length of one of its diagonals is 24 centimetres. Compute the following measurements of this rhombus.
i) Length of the second diagonal
ii) Length of a side
iii) Perimeter
iv) Distance between sides
Length of a diagonal (d1) = 24 cm
Area of the rhombus = 216 cm2
Area of the rhombus =
× d1 × d2
× d1 × d2 = 216
d1 × d2 = 432
24 × d2 = 432
d2 = 18 cm
(i) length of another diagonal = 18 cm

We can see that some part of the rhombus constitutes a right-angle triangle.
From that
H2 = 92 + 122
H = √225
= 15
(ii)∴ side of a rhombus is 15 cm
We know that sides are equal in a rhombus
(iii) So, perimeter = 4 × sides
= 4 × 15
= 60 cm
(iv) In rhombus distance between the side is also a side
∴ distance between the side is 15 cm
Couldn't generate an explanation.
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