Q97 of 107 Page 104

Thrice a number decreased by 5 exceeds twice the number by 1. Find the number.

Let the number be x. Then, thrice the number = 3x and twice of this number = 2x.


If we decrease thrice of x by 5, we get (3x – 5).


According to the question,


(3x – 5) – 2x = 1


⇒ 3x – 5 –2x = 1


⇒ x – 5 = 1


⇒ x = 1 + 5


⇒ x = 6


Hence, the required number is 6.


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