The aqueous solution having pH 11 is how many times less basic than aqueous solution having pH 8?

A) solution with pH = 11

pH + pOH = 14

Therefore, pOH = 14-11 = 3

Hence, [OH^-] = 10^-3

B) solution with pH = 8

pOH = 14-8 = 6

Hence, [OH^-] = 10^-6

So the solution with pH = 11 is (10^-3÷10^-6) 1000 times more basic than the solution with pH = 8