What will be OH^- concentration in an aqueous solution having pH = 8?

The formula to calculate pOH is as follows:

pOH = -log₁₀[OH^-]

Also, the relation between pH and pOH is: pH + pOH = 14

Therefore, pOH = 14- 8 = 6

Now, using the formula of pOH:

6 = -log₁₀[OH^-]

Therefore, the concentration of hydroxide ions is 1 x 10^-6 M.