is a diameter of ⨀(O, 10). A tangent is drawn from B to ⨀(O, 8) which touches ⨀(O, 8) at D.
intersects 0(0, 10) in C. Find AC.

Given that AB is a diameter of circle (O, 10).
⇒ OA = OB = 10 = radius
⇒ AB = 20 = diameter
Also given a tangent is drawn from B to circle (O, 8) which touches the circle at D.
⇒ OD = 8 = radius
Since BD is a tangent, OD ⊥ BD.
And since the angle is inscribed in a semi circle, ∠ACB = 90°.
⇒ ∠ODB = ∠ACB = 90°
∴ ∠DBO ≅ ∠CBA
By AA theorem,
Thus, correspondence ODB ↔ ACB is a similarity.
Then
= ![]()
⇒
= ![]()
⇒ AC =
= 16
∴ AC = 16
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