Q10 of 31 Page 234

P is in exterior of ⨀(O, 15). A tangent from P touches the circle at T. If PT = 8, then OP = ………..

Given P is in exterior of circle (O, 15) and a tangent from P touches the circle at T.


Thus, ∠OTP = 90°



By Pythagoras Theorem,


⇒ OP2 = OT2 + TP2


⇒ OP2 = 152 + 82


= 225 + 64


= 289


∴ OP = 17

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