Q10 of 31 Page 234

A chord of ⨀(O, 5) touches ⨀(O, 3). Therefore the length of the chord =

Given chord of circle (O, 5) touches circle (O, 3).


Radius of smaller circle OM = 3 and radius of bigger circle OB = 5



In right angled ΔOMB,


⇒ OB2 = OM2 + MB2


⇒ 52 = 32 + MB2


⇒ MB2 = 25 – 9 = 16


⇒ MB = 4


Length of chord AB = 2 (MB) = 2 (4) = 8

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