Q10 of 31 Page 234

In ΔABC, AB = 3, BC = 4, AC = 5, then the radius of the circle touching all the three sides is ………..

Given in ΔABC, AB = 3, BC = 4, AC = 5.



By Pythagoras Theorem,


⇒ AC2 = AB2+ BC2


⇒ 52 = 32 + 42


⇒ 52 = 9 + 16


⇒ 52 = 52


∴ ΔABC is a right angled triangle and ∠B is a right angle.


We know that the radius of the circle touching all the sides is .


⇒ The required radius of circle =


=


= 1

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