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10th term of arithmetic progression 2, 7, 12, ….

The given arithmetic progression is 2, 7, 12, …
Its first term a = 2
Common difference = d = 7 – 2 = 5.
So nth term an of the given arithmetic progression is given by
an = a + (n -1)d


Where,


a = First term of AP
d = Common difference of AP
and no of terms is ‘n’



Thus 10th term a10 = 2 + (10 - 1) × 5.
⇒ a10 = 2 + 9 × 5 = 2 + 45 = 47


Hence, 10th term is 47.


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