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24^th term of arithmetic progression 9, 13, 17, 21, ….

The given arithmetic progression is 9, 13, 17, 21, …
Its first term a = 9
Common difference = d = 13 – 9 = 4.
So n^th term a_n of the given arithmetic progression is given by
a_n = a + (n -1)d

Where,

a = First term of AP
d = Common difference of AP
and no of terms is ‘n’

Thus 24^th term a₂₄ = 9 + (24 - 1) × 4.
⇒ a₂₄ = 9 + 23 × 4 = 9 + 92 = 101

Hence, 24^th term is 101.