Write 5th term from end of the arithmetic progression 3, 5, 7, 9, …, 201.
Here last term of the progression l = 201.
First term a = 3 and common difference = 5 – 3 = 2
We know, In an AP, the nth term from last is
an = l – (n – 1)d
where an is nth term from last, l is last term and ‘d’ is common difference.
Thus 5th term from the end
= l – (5 -1)d
= 201 – (4) × (2)
= 201 - 8
= 193
Hence, 5th term from the last is 193.
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