Prove the following with the help of identities:
sin2θ cosθ + tanθsinθ + cos3θ = secθ
Taking L.H.S we get,
Rearranging the terms ;
Sin2 θ.cos θ + cos3 θ + tan θ.sin θ
⇒ cos θ(sin2 θ + cos2 θ) + tan θ.sin θ
⇒ cos θ (1) + ![]()
⇒ cos θ + ![]()
⇒ ![]()
⇒
= sec θ
= R.H.S
Hence, proved.
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