Q10 of 48 Page 86

Prove the following:

Taking L.H.S we get,


sin (90˚ – θ)cos(90˚ – θ)


⇒ cos θ.sin θ


⇒ (Writing 1 as sin2 θ + cos2 θ.)


Dividing by cos2 θ to both numerator and denominator


⇒


⇒


⇒


= R.H.S


Hence, proved.


More from this chapter

All 48 →
8

Prove the following:

sin 35° sin 55° – cos 35° cos 55° = 0

 9

Prove the following:

 11

Prove the following:

 12

Prove the following: