Prove the following with the help of identities:

Taking L.H.S we get,
![]()
⇒ ![]()
⇒ ![]()
Taking L.C.M and using: a3 – b3 = (a – b)(a2 + b2 + ab)
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ cot θ + tan θ + 1
⇒
+1
⇒
+ 1
⇒ cosec θ.sec θ + 1
= R.H.S
Hence, proved.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.