Prove the following with the help of identities:
(sin A + cosec A)2 + (cos A + sec A)2 = 7 + tan2A + cot2A
Taking L.H.S we get,
(sin A + cosec A)2 + (cos A + sec A)2 = 7 + tan2 A + cot2 A
Expanding the terms using: (a + b)2 = a2 + b2 + 2.a.b
⇒ sin2 A + cosec2 A + 2.sin A.cosec A + cos2 A + sec2 A + 2.sec A.cos A
⇒ (sin2 A + cos2 A) + 2.sin A.
+ cosec2 A + sec2 A + 2.cos A.![]()
⇒ 1 + 2 + cosec2 A + sec2 A + 2
⇒ 5 + (1 + cot2 A) + (1 + tan2 A)
⇒ 5 + 1 + 1 + tan2 A + cot2 A
⇒ 7 + tan2 A + cot2 A
= R.H.S
Hence, proved.
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