Q2 of 82 Page 121

By calculating the following polynomials f(x) let us write the values of f(1) and f(–1):

f(x) = 4 + 3x – x3 + 5x6

Formula used/Theory.


Putting the value of ‘x’ in f(x) gives out the value of f(x) on ‘x’


We have,


f(x) = 4 + 3x – x3 + 5x6


When we put x = 1


Then,


f(1) = 4 + 3 × 1 – 1 + 5 × 1


f(1) = 4 + 3 – 1 + 5


f(1) = 11


When we put x = -1


Then,


f(-1) = 4 + 3 × (-1) – (-1)3 + 5 × (-1)6


f(-1) = 4 + 3 × (-1) – (-1) + 5 × (-1)


f(-1) = 4 – 3 + 1 + 5


f(-1) = 7


Conclusion.


The value of f(1), f(-1) are 11, 7 respectively.


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Let us check the following statements—

The zero of the polynomial P(x) = x – 1 is 1.