By applying Remainder Theorem, let us calculate and write the remainders, that I shall get when the following polynomials are divided by (x – 1).

x³ – 6x² + 13x + 60

Remainder theorem says that,

f(x) is a polynomial of degree n (n ≥ 1) and ‘a’ is any real number. If f(x) is divided by (x – a), then the remainder will be f(a).

Let us solve the following questions on the basis of this remainder theorem.

Let f(x) = x³ – 6x² + 13x + 60 …(1)

When x³ – 6x² + 13x + 60 is divided by (x – 1).

Now, let’s find out the zero of the linear polynomial, (x – 1).

To find zero,

x – 1 = 0

⇒ x = 1

This means that by remainder theorem, when x³ – 6x² + 13x + 60 is divided by (x – 1), the remainder comes out to be f(1).

From equation (1), remainder can be calculated as,

Remainder = f(1)

⇒ Remainder = (1)³ – 6(1)² + 13(1) + 60

⇒ Remainder = 1 – 6 + 13 + 60

⇒ Remainder = -5 + 73

⇒ Remainder = 68

∴ the required remainder = 68