Q4 of 81 Page 153

Let us show that,

Given:

3√48-4√75 + √192 = 0


Take L.H.S. = 3√48-4√75 + √192


It can be written as:


3√(2×2×2×2×3)-4√(3×5×5) + √(2×2×2×2×2×2×3)


= 12√3-20√3 + 8√3


= -8√3 + 8√3


= 0 = R.H.S.


Hence, L.H.S. = R.H.S.


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