If 
let us calculate simplified of i. 
and ii. 
Formula used.
(a + b)2 = a2 + b2 + 2ab
(a + b)3 = a3 + b3 + 3ab(a + b)
Let a = m and b = 
(a + b)2 = a2 + b2 + 2ab
(m + 
)2 = m2 + 
2 + 2 × m × 
(√3)2 = m2 + 
+ 2 × 1
3 = m2 + 
+ 2
m2 + 
= 3 – 2 = 1
(a + b)3 = a3 + b3 + 3ab(a + b)
(m + 
)3 = m3 + 
3 + 2 × m × 
× (m + 
)
(√3)3 = m3 + 
+ 2 × 1 × (√3)
3√3 = m3 + 
+ 2√3
m3 + 
= 3√3 – 2√3 = √3[3 – 2]
= √ 3
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