If
and
the value of (a2 + b2) is
a + b = √5
a = √5 – b
a–b = √3
(√5 – b) – b = √3
2b = √5 - √3
b = ![]()
a = √5 – b = √5 –
= ![]()
ab =
×
=
= ![]()
(a + b)2 = a2 + b2 + 2ab
(√5)2 = a2 + b2 + 2 × ![]()
a2 + b2 = 5 – 1 = 4
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