Q6 of 81 Page 161

If and let us calculate the followings :


a + b =


a + b = = = = 3


a-b =


a-b = = = = √5


ab = = 1


(a + b)3 = a3 + b3 + 3ab(a + b)


a3 + b3 = (a + b)3 - 3ab(a + b)


= (3)3 – 3 × 1 × 3


= 27 – 9 = 18


(a-b)3 = a3-b3-3ab(a-b)


a3-b3 = (a-b)3 + 3ab(a-b)


= (√5)3 + 3 × 1 × (√5)


= 5√5 + 3√5


= √5 [5 + 3]


= 8√5



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