A tangent drawn to a circle with centre O from an external point A touches the circle at the point B. If OB = 5cm, AO = 13cm, then the length of AB is
The ΔABO formed by joining the three points is always a right angled triangle
AO is the hypotenuse of Δ ABO
Applying Pythagoras theorem :
AB2 = AO2-OB2
⇒ AB2 = 132-52
⇒ AB2 = 169-25
⇒ AB2 = 144
⇒ AB = 12 cm.
So Correct Option is (A)
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