Q12 of 31 Page 218

In the adjoining figure O is the centre and BOA is a diameter of the circle. A tangent drawn to a circle at the point P intersects the extended BA at the point T. If PBO = 30°, let us find the value of PTA.

PBO = 300 (Given)


OPB = 300 (Δ PBO is an isosceles triangle)


OPT = 900 (Tangents are perpendicular to the line joining the centre of the circle)


BPT = (900 + 300) = 1200


PTA = 1800–(1200 + 300) = 300 (Sum of interior angles of Δ BPT)


More from this chapter

All 31 →