The length of a radius of a circle with its centre O is 5 cm. and the length of its chord AB is 8 cm. Let us write by calculating, the distance of the chord AB from the centre O.

Given radius = 5cm, AB = 5cm
Perpendicular from the center of the circle to any Chord bisects it in two line segments

So, AD = BD
In
ODB
OB = 5cm
BD = 4cm
Using Pythagoras Theorem
base2 + Height2 = Hypotenuse2
⇒ OD2 + DB2 = OB2
⇒ OD2 = 25-16
⇒ OD2 = 9
⇒ OD = 3cm
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