Q16 of 31 Page 65

Ab and CD are two equal chords of a circle with its centre O. If the distance of the chord AB from the point O is 4 cm. Then the distance of the chord from the centre O of the circle is


In AOB and COD


AB = CD


OA = OC = OB = OD


SSS Congruency.


So each and every angles and sides should be equal.


OAB = OCD = OBA = ODC


⇒ EA


⇒ FC


⇒ AB = CD


So, EA = FC


In AOE and COE


⇒ EA = FC


⇒ EAO = FCO


⇒ OA = OC


SAS Congruency.


So, By CPCT OE = OF = 4cm

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