Q3 of 31 Page 65

The length of a chord PQ of a circle with its centre O is 4 cm. and the distance of PQ from the point O is 2.1 cm. Let us write by calculating, the length of its diameter.


Given PQ = 4cm, Distance from the Center is 2,1cm


PQ = 2 PD


Perpendicular from the center of the circle to any Chord bisects it in two line segments



⇒ PD


⇒ PD = 2cm


In O PD , Using Pythagoras Theorem


⇒ OD2 + PD 2 = OP2


⇒ OP2 = 2.12 + 22


⇒ OP2 = 8.41


⇒ OP = 2.9cm


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